(2x^2)+(3y^2)-(2xy)=10

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Solution for (2x^2)+(3y^2)-(2xy)=10 equation: 


Simplifying
(2x2) + (3y2) + -1(2xy) = 10

Remove parenthesis around (2xy)
(2x2) + (3y2) + -1 * 2xy = 10

Multiply -1 * 2
(2x2) + (3y2) + -2xy = 10

Reorder the terms:
-2xy + (2x2) + (3y2) = 10

Solving
-2xy + (2x2) + (3y2) = 10

Solving for variable 'x'.

Reorder the terms:
-10 + -2xy + (2x2) + (3y2) = 10 + -10

Combine like terms: 10 + -10 = 0
-10 + -2xy + (2x2) + (3y2) = 0

The solution to this equation could not be determined.

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